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canvas.school.edu / physics / quiz-4
Question 7 of 12

A ball is dropped from a height of 48.3 meters. Ignoring air resistance, how long does it take to hit the ground?

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Answer
01Use h = ½ g t² with g ≈ 9.8 m/s².
02Solve for t: t = √(2h / g).
03t = √(2·48.3 / 9.8) ≈ 3.14 s.
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Wait, why is g negative in step 2? I got confused.
Good catch. We're picking down as the positive direction here, so gravity comes out as +9.8 m/s². If you set up as positive instead, then g = −9.8. Either works — you just have to be consistent with the sign of your height.
Try an example →Explain simpler
Ok got it. Can you quiz me on this?
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